Answer:
The cost of making the 10th frame is 9765625
Explanation:
Topic: Geometric Progression
Literally, what is being asked in the question is to get the 10th term of a geometric progression.
This can be done in two ways.
The first way is by multiplying 5 in 10 places;
i.e.
![5^(10) = 9765625](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3vjbwxxqly6w77sfcuo516unohzq4658jl.png)
But what if we're dealing with a kind of difficult combination of numbers.
Follow the highlighted steps below, to solve this question.
Given:
Cost of first frame = 5 nickels
Additional frame cost a multiple of 5
We're to calculate the payment for making 10 frames;
Using the geometric Formula
![T_(n) = ar^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hott9g7w7sj2toa2nzckseue7m7jmjcuyj.png)
Where a = first term = cost of first nickel = 5
r = common ratio = multiple of 5
n = 10th nickel
Tn = Cost of the tenth nickel; i.e
![T_(10)](https://img.qammunity.org/2020/formulas/mathematics/college/8b5g79k273k5wwzp8fc5dl44ksmu5wmwdp.png)
By Substitution
becomes
![T_(10) = 5 * 5^(10-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gus24dx1zqfy4leg5dgi67vogg1yhvjqi8.png)
![T_(10) = 5 * 1953125](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2wa0rekxt35fh9fjcl6jedei3w52huql8p.png)
![T_(10) = 9765625](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hqtjts3a6ssjjhleb7x70j16jaa282jhlz.png)
Hence, the cost of making the 10th frame is 9765625