Question

The amount of gas that occupies 36.52 L at 68.0 degrees Celsius and 672 mm Hg is ___ Mol.

Answer 1

1.15 moles

Step-by-step explanation:

The ideal gas law is written as
`PV=nRT`

where
`P,V,T`are the pressure, volume and temperature,
`n` is the number of moles of gas; and
`R` is the ideal gas constant. It is the same for all gases.

Given,
`P=672 mm of Hg=0.8842 \text{ atm}`

`V=36.52L`

`T=`
`68^(0) C=`
`341.15K`

`R=0.0821\text{ atm L }moles^(-1)K^(-1)`

Since,
`n=(PV)/(RT) =(0.8842* 36.52)/(0.0821* 341.15)=1.15\\`

So,the number of moles is
`1.15`