Answer:
c=0.392
Explanation:
Given that X1,...,Xn form a random sample from the normal distribution with unknown mean μ and known variance 1.
Suppose also that μ0 is a certain specified number, and that the following hypotheses are to be tested:
![H0: \mu = \mu_0 Vs H_1: \mu \\eq \mu_0](https://img.qammunity.org/2020/formulas/mathematics/high-school/w5u79philhy2v51gpo6eq6aip6qq5z9581.png)
This is two tailed test.
Alpha =0.05
Sample size = 25
we reject null hypothesis if
![\frac|{(1)/(√(25) ) } \geq 1.96](https://img.qammunity.org/2020/formulas/mathematics/high-school/hcrcg888r7xhvxa5dqjqzz8drs80t6254p.png)
Or
![|x_n - \mu_0|\geq 1.96/5 = 0.392](https://img.qammunity.org/2020/formulas/mathematics/high-school/i784zejobvxjo1cx3q8t1ohh70qhlclyka.png)