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Suppose we have an infinitely long wire carrying a current of 5.5 A. It is bent into an L-shape extending into positive infinities along the x- and y-axes. Find the magnitude of the magnetic field (in T) at a point P with coordinates (0.6 m, 0.6 m).

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Answer:

The magnitude of the magnetic field at point T is
3.13* 10^(- 6)\ T

Solution:

As per the question:

Current, I = 5.5 A

From the figure shown:


\theta = 45^(\circ)

Now, the net magnetic field, B at the point is given by:

Magnetic field due to one part of the wire,


B = (\mu_(o)I)/(4\pi r)(sin\theta+ sin90^(\circ)) = (\mu_(o)I)/(4\pi r)(sin\theta + sin90^(\circ))


B' = 2* B


B' = 2* (\mu_(o)I)/(4\pi r)(sin45^(\circ) + sin90^(\circ))


B' = 2* (\mu_(o)I)/(4\pi r)((1)/(√(2)) + 1)


B' = (2* 10^(- 7)* 5.5)/(0.6)((1)/(√(2)) + 1)


B' = 3.13* 10^(- 6)\ T

Suppose we have an infinitely long wire carrying a current of 5.5 A. It is bent into-example-1
User Eluong
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