Write an equation in slop-intercept form for the line that passes through (-3,1) and is parallel to y=2x-4

Question

asked Jan 8, 2020 6.2k views

1 Answer

FrostbiteXIII · Answer 1 · 2020-01-12T17:46:00+0000

Answer:

The equation of line in slop-intercept form is given by:

Explanation:

Given equation of line:

y=2x-4

To find the equation of line parallel to the line of the given equation and passes through point (-3,1).

Applying slope relationship between perpendicular lines.

where
m_1 and
m_2 are slopes of parallel lines.

For the given equation in the form
y=mx+b the slope
m_2 can be found by comparing
y=2x-4 with standard form.

∴
m_2=2

Thus slope of line parallel to this line
m_1 would be given as:

∴
m_1=2

The line passes through point (-3,1)

Using point slope form:

Where
$(x_1,y_1)\rightarrow (-3,1)$ and
m=m_2=2

So,

y-1=2(x-(-3))

y-1=2(x+3)

Using distribution.

y-1=(2* x)+(2* 3)

y-1=2x+6

Adding 1 to both sides.

y-1+1=2x+6+1

y=2x+7

Thus the equation of line in slop-intercept form is given by: