Question

How do you find the derivative of h(t)=sqrt(t)(1-t^2)

Answer 1

Explanation:

`h(t)=√((t)(1-t^2))\\h^(2)(t)=t(1-t^2)=t-t^3\\ diff. w.r.t.,\\2 h(t)h'(t)=1-3t^2\\h'(t)=(1-3t^2)/(2 h(t)) \\h'(t)=(1-3t^2)/(2√((t)(1-t^2)) )`