Question

What is the equation for the line that passes through (-4,-3) and (-2,3)

Answer 1

Answer:
`y=3x+9`

Explanation:

The equation of the line in Slope-Intercept form is:

`y=mx+b`

Where "m" is the slope and "b" is the y-intercept.

We can calculate the slope of the line with this formula:

`m=(y_2-y_1)/(x_2-x_1)`

Given these points:

`(-4,-3)\\\\ (-2,3)`

We can identify that:

`y_2=-3\\y_1=3\\\\x_2=-4\\x_1=-2`

Then, the slope is:

`m=(-3-3)/(-4-(-2))=3`

Now we have to substitute the slope and one of the points into
`y=mx+b` and solve for "b":

`3=3(-2)+b\\\\3+6=b\\\\b=9`

Then, the equation of this line is:

`y=3x+9`