Question

The density of Nitrogen (N2) gas in a 4.32 L container at our

na 4.32 L container at 837 torr and 45.0 °C is​

Answer 1

δ N2(g) = 1.1825 g/L

Step-by-step explanation:

• δ ≡ m/v
• Mw N2(g) = 28.0134 g/mol

ideal gas:

• PV = RTn

∴ P = (837 torr)×( atm/760 torr) = 1.1013 atm

∴ T = 45.0 °C + 273.15 = 318.15 K

∴ R = 0.082 atm.L/K.mol

⇒ n/V = P/R.T

⇒ n/V = (1.1013 atm) / ((0.082 atm.L/K.mol)(318.15 k))

⇒ n/V = 0.0422 mol/L

⇒ δ N2(g) = (0.042 mol/L)×(28.0134 g/mol) = 1.1825 g/L