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The capacity of an elevator is 15 people or 2400 pounds. The capacity will be exceeded if 15 people have weights with a mean greater than 2400/15=160 pounds. Suppose the people have weights that are normally distributed with a mean of 167 lb and a standard deviation of 29 lb. find the probability that if a person is randomly selected, his weight will be greater than 160 pounds.

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Answer:

0.5987

Explanation:


\mu = 167


\sigma = 29

We are supposed to find the probability that if a person is randomly selected, his weight will be greater than 160 pounds.

Formula :
Z=(x-\mu)/(\sigma)

P(x>160)

Substitute the values in the formula :


Z=(160-167)/(29)


Z=−0.241

Refer the z table for p value

p value = 0.4013

P(x>160)= 1-P(x<160)=1-0.4013=0.5987

Hence the probability that if a person is randomly selected, his weight will be greater than 160 pounds is 0.5987

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