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In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres of masses 1.56 kg and 21.1 g whose centers are separated by 5.34 cm. Calculate the gravitational force between these spheres, treating each as a point mass located at the center of the sphere. The value of the universal gravitational constant is 6.67259 × 10−11 N · m2 /kg2 .

User Jemimah
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2 Answers

4 votes

Final answer:

The gravitational force between the two lead spheres is calculated using Newton's law of universal gravitation and is found to be approximately 1.2009 × 10−9 Newtons, using the provided mass and distance values along with the universal gravitational constant G.

Step-by-step explanation:

The student has asked for the calculation of the gravitational force between two lead spheres using the universal gravitational constant G. To calculate this force, we use Newton's law of universal gravitation, which is given by the equation F = G(m1)(m2)/r^2, where F is the gravitational force, m1 and m2 are the masses of the two objects, r is the distance between the centers of the two masses, and G is the universal gravitational constant.

The student has asked for the calculation of the gravitational force between two lead spheres using the universal gravitational constant G. To calculate this force, we use Newton's law of universal gravitation, which is given by the equation F = G(m1)(m2)/r^2, where F is the gravitational force, m1 and m2 are the masses of the two objects, r is the distance between the centers of the two masses, and G is the universal gravitational constant.

Given that G = 6.67259 × 10−11 N · m2/kg2, m1 = 1.56 kg, m2 = 21.1 g (which is 0.0211 kg) and r = 5.34 cm (which is 0.0534 m), we can plug these values into the equation to calculate the force:

F = (6.67259 × 10−11) × (1.56) × (0.0211) / (0.0534)^2

F = 1.2009 × 10−9 Newtons

Thus, the gravitational force between the two lead spheres is approximately 1.2009 × 10−9 Newtons.

User Jimmy Ko
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5 votes

Answer:


F = 7.7*10^(-10)N

Step-by-step explanation:

You need to be careful with units for this problem. The force will be:


F =(K*m1*m2)/(d^2)


F=(6.67259 * 10^(-11)*1.56*21.1*10^(-3))/((5.34*10^(-2))^2)


F=7.7*10^(-10)N

User Angshuman Agarwal
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