Question

what volume of ethylene gas at 293K and 102kPa must be compressed to yield 295m3 of ethylene gas at 808kPa and 585K​

Answer 1

1170.43 m³

Step-by-step explanation:

We are given;

• Initial pressure, P1 as 808 kPa
• Initial temperature, T1 as 585 K
• Initial volume, V1 as 295 m³
• New pressure, P2 as 102 kPa
• New temperature, T2 as 293 K

We are required to find the new volume;

• We are going to use the combined gas law
• According to the gas law;
  `(P1V1)/(T1)=(P2V2)/(T2)`
• Thus, rearranging the formula;

`V2=(P1V1T2)/(P2T1)`

`V2=((808 kPa)(295)(293K))/((102 kPa)(585K))`

`V2=1170.43`

Therefore, the volume is 1170.43 m³