Question

A simple pendulum having a length of 2.61 m and a mass of 3.93 kg undergoes simple harmonic motion when given an initial speed of 2.45 m/s at its equilibrium position. Determine its period. The acceleration due to gravity is 9.8 m/s 2 . Answer in units of s.

Answer 1

T=3.24s

Step-by-step explanation:

Period of a simple pendulum is given by:

`T=2*\pi*√(L/g)`

`T=2*\pi*√(2.61/9.8)`

`T=3.24s`

As you can see, it doesn't depend on the mass of the object, nor its speed.