Question

3. What is the volume of 0.750 mol of argon at STP?​

Answer 1

The volume is 16.7 liters.

Step-by-step explanation:

STP conditions are:

1 atm as pressure

273 K as temperature (0°C)

So let's get the volume by the Ideal Gas Law, replacing the values.

P . V = n . R . T

1 atm . V = 0.750 moles . 0.082 L.atm /mol.K . 273 K

V = (0.750 moles . 0.082 L.atm /mol.K . 273 K) / 1 atm

V = 16.7 L