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a skydiver accelerates form 0m/s to 5m/s at an acceleraton of 10/s. how far do the fall during his aceleration???

User ThomasGth
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1 Answer

3 votes

Answer:

1.25meters of falling

Step-by-step explanation:


{v}^(2) = {v0}^(2) + 2ax \\ 25 = 0 + 20x \\ 25 = 20x \\ x = 1.25

User Moien
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