Question

Taru and Reiko simultaneously grab a 1.63 kg piece of rope and begin tugging on it in opposite directions. If Taru pulls with a force of 23.4 N and the rope accelerates away from her at 1.66 m/s2, with what force is Reiko pulling? Round your answer to 2 decimal places.

Answer 1

Fr = 26.105 N

Step-by-step explanation:

The force is equal to mass by the acceleration in this case the net force is the summation of both forces so

From Ft=Force Taru, Fr= ? , m=1.63kg, a=1.66m/s^2

Fnet = m*a

(Fr - Ft) = m*a

Fr = m*a + Ft

→ Replacing numeric

Fr = 1.63kg*1.66m/s^2 + 23.4N =

Fr = 26.105 N