Question

A 5.58 kg object with a speed of 35 m/s strikes a steel plate at an angle of 45.0 degrees with the normal to the plate, and rebounds at the same speed and angle on the other side of the normal. What is the change (in magnitude only) of the linear momentum of the object (in kilogram-meters/second)?

Answer 1

magnitude of vector is 276.19 kg m/s

Step-by-step explanation:

The initial momentum is vector of magnitude

`5.58 * 35 = 195.3 (kg m/s)` And driven in a coherent manner with initial vector.

same magnitude is momentum after the impact, but it is oriented perpendicularly to initial momentum vector.

So, you have 2 momentum vector of specified magnitude perpendicular to one another.

The contrast between such two vectors is a right angle triangle hypotenuse of 195.3 sides

magnitude of vector is
`√( 195.3^2 + 195.3^2) = 276.19`