Question

PLEASE HURRY Study these equations: f(x) = 2x – 8 g(x) = –5x What is h(x) = f(x)g(x)? h(x) = 10x2 – 40x h(x) = –10x2 + 40x h(x) = –10x + 40 h(x) = 10x – 40

Answer 1

B : h(x) = –10x2 + 40x

Explanation:

this is a late answer but I hope it helps anyone who needs it for the future !!

Answer 2

h(x)=
`-10x^(2)+40x`

Explanation:

given ,
`f(x)=2x-8`

given,
`g(x)=-5x`

Given that
`h(x)=f(x)g(x)`

Let
`t_(1)` be
`k_(1)x^{n_(1)}` where
`k_(1) \text{ and } n_(1) \text{ are constants}`

Let
`t_(2)` be
`k_(2)x^{n_(2)}` where
`k_(2) \text{ and } n_(2) \text{ are constants}`

We know that
`t_(1)* t_(2)=k1* x^{n_(1)}* k2* x^{n_(2)}`=
`k_1k_2x^{n_(1)+n_(2)}`

So,
`h(x)=(2x-8)(-5x)`=
`-10x^(2)+40x`