Question

The rate of disappearance of HBr in the gas phase reaction 2HBr(g) → H2 (g) I2 (g) is 0.190 M s-1 at 150°C. The rate of appearance of H2 is ________ M s-1. Group of answer choices

Answer 1

The rate of appearance of hydrogen gas is 0.095 M/s.

Step-by-step explanation:

Rate of the reaction is the change in concentration of of any one of the reactants or products per unit time.

`2HBr(g)\rightarrow H_2 (g) I_2 (g)`

Given:

The rate of disappearance of HBr =
`-(d[HBr])/(dt)=0.190 M/s`

Rate of the reaction is given by:

`R=-(1)/(2)(d[HBr])/(dt)=(1)/(1)(d[H_2])/(dt)`

`R=-(1)/(2)(d[HBr])/(dt)=(1)/(2)* 0.190 M/s=0.095 M/s`

Rate of appearance of the hydrogen gas:

`(d[H_2])/(dt)=R =0.095 M/s`

The rate of appearance of hydrogen gas is 0.095 M/s.