Step-by-step explanation:
Problem 1.
Initial speed of the runner, u = 0
Acceleration of the runner,
![a=4.2\ m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/vryatfoe5woadh264qjebvzfwonwpboza4.png)
Time taken, t = 100 s
Let v is the speed of the runner now. Using the first equation of kinematics as :
![v=u+at](https://img.qammunity.org/2020/formulas/physics/middle-school/8u69t2dm31jy4f6e8h3i9msisjzkrvuvq4.png)
![v=at](https://img.qammunity.org/2020/formulas/physics/middle-school/lou86jrirdw7ahqbib4nzxwyep7kg557ig.png)
![v=4.2\ m/s^2* 100\ s](https://img.qammunity.org/2020/formulas/physics/middle-school/na6an6dsfwlwudp9ttw2qlvrbxi3cyx5rs.png)
v = 420 m/s
Problem 2.
Initial speed of the plane, u = 0
Distance covered, d = 300 m
Time taken, t = 25 s
Using the equation of kinematics as :
![d=ut+(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/college/cnmnl56g8a1pmreipfvlacntz8hqzm02l7.png)
![d=(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/oufq2zmjo6qnhvtb2flz2pxty76b5m6dxe.png)
![a=(2d)/(t^2)](https://img.qammunity.org/2020/formulas/physics/college/jbjh294n37krh30kf1zz5auietjqtnz6dl.png)
![a=(2* 300\ m)/((25\ s)^2)](https://img.qammunity.org/2020/formulas/physics/middle-school/enph30x8wpl78j6uqxg3qki6fzjr00zn77.png)
![a=0.96\ m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/kro8pgmrmin3a40z4kh301og8s8kulohnr.png)
Problem 3.
A ball free falls from the top of the roof for 5 seconds. Let it will fall at a distance of d. It is given by :
![d=ut+(1)/(2)gt^2](https://img.qammunity.org/2020/formulas/physics/middle-school/8o4p2gnyvyewda0eq74yh23uu2kese2op8.png)
![d=(1)/(2)* 9.8* (5)^2](https://img.qammunity.org/2020/formulas/physics/middle-school/m3efw7x3an38pgyuhnxmo1hnnt6binll88.png)
d = 122.5 meters
Let v is the final speed at the end of 5 seconds. Again using first equation of kinematics as :
![v=u+gt](https://img.qammunity.org/2020/formulas/physics/college/a8ot8d7m0rb3rzmtu2a9fw3d987ouvfrlh.png)
![v=9.8\ m/s^2* 5\ s](https://img.qammunity.org/2020/formulas/physics/middle-school/ignspjrx5kptc3aptzqqx6h7lpugk1v7rq.png)
v = 49 m/s
Hence, this is the required solution.