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Given the solutes NaCl and I2 and the solvents NH3(ℓ) and C7H16 (heptane), which is true?

NaCl and I2 are both more soluble in NH3 than in C7H16.
NaCl and I2 are both more soluble in C7H16 than in NH3.
NaCl is more soluble in NH3; I2 is more soluble in C7H16.
NaCl is more soluble in C7H16; I2 is more soluble in C7H16.
In order to determine relative solubilities in these cases one must know whether the solution reactions are exothermic or endothermic.

User Kesavan R
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1 Answer

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Answer:

NaCl is more soluble in NH3 and I2 is more soluble in C7H16

Step-by-step explanation:

Polar substances are likely to dissolve in polar solvents. For example, ionic compounds, which are very polar, are often soluble in the polar solvent water. Nonpolar substances are likely to dissolve in non-polar solvents.For example, ionic compounds are insoluble in hexane.

In the above example NaCl is a polar compound made up of ions
Na^(+)  and \text{ }cl^(-) so it is soluble in polar compounds like ammonia (NH3),where as I2 is a non-polar solid so it is soluble in non-polar solvents like n-heptane(C7H16).

User Svltmccc
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