Answer:
The directrix of parabola
is the line x = +10.
Explanation:
The general form of parabola is given as
![y^2 = 4px](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f8nm3m4lkr2qqyfdyrcy51e5i5actx6bxh.png)
where the directrix is the vertical line x = - p .
If p > 0, then parabola opens to the right.
If p < 0 then parabola opens to the left.
Now here, the given equation is
![y^2 = -40x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3muctonsozdn8f7x8slyzbvfq6qvuy1ljs.png)
Representing the given equation in standard form:
![y^2 = 4(-10) x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v7yeo153j6fz3uv6yj6plkbucvstmij1zy.png)
⇒ p = -10
So, the directrix of the parabola is x = - p = - (-10) = 10
or, x = + 10
Hence, the directrix of parabola
is the line x = +10.