Question

Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2​

Answer 1

`-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...`

Explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

`a_n=a_1+(n-1)d`

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

`a_1=-10\\d=-2`

substitute

`a_n=-10+(n-1)(-2)`

`a_n=-10-2n+2`

`a_n=-2n-8`

so

Find the first ten terms

`a_1=-10`

For n=2 ---->
`a_2=-2(2)-8=-12`

For n=3 ---->
`a_3=-2(3)-8=-14`

For n=4 ---->
`a_4=-2(4)-8=-16`

For n=5 ---->
`a_5=-2(5)-8=-18`

For n=6 ---->
`a_6=-2(6)-8=-20`

For n=7 ---->
`a_7=-2(7)-8=-22`

For n=8 ---->
`a_8=-2(8)-8=-24`

For n=9 ---->
`a_9=-2(9)-8=-26`

For n=10 ---->
`a_1_0=-2(10)-8=-28`

The sequence is

`-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...`