Question

PH is 7.45. Calculate value of [H3O+] and [OH-]

Answer 1

The answer is (H30+) =3,55e-8M and (OH-)=2,82e-7M

Step-by-step explanation:

We use the formulas:

pH= - log(H30+) and Kwater=(H30+)x(OH-)

pH= - log(H30+) ----< (H30+)= antilog- pH=antilog- 7,45=3,55E-8M

Kwater=(H30+)x(OH-)

(OH-)=Kwater/(H30+)= 1,00e-14/3,55e-8 = 2,82e-7