Question

Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFraction negative 5 + StartRoot 57 EndRoot Over 2 EndFraction StartFraction negative 5 minus StartRoot 7 EndRoot Over 2 EndFraction comma StartFraction negative 5 + StartRoot 7 EndRoot Over 2 EndFraction StartFraction 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFraction 5 + StartRoot 57 EndRoot Over 2 EndFraction StartFraction 5 minus StartRoot 7 EndRoot Over 2 EndFraction comma StartFraction 5 + StartRoot 7 EndRoot Over 2 EndFraction

Answer 1

B is your answer!

Explanation:

I just did it and got it correct

Answer 2

`x=(-5-√(57) )/(2)\ or\ x=(-5+√(57) )/(2)`

Explanation:

Given:

The equation to solve is given as:

`x^2=-5x+8`

Rearrange the given equation in standard form
`ax^2+bx +c =0`, where,
`a,\ b,\ and\ c` are constants.

Therefore, we add
`5x-8` on both sides to get,

`x^2+5x-8=0`

Here,
`a=1,b=5,c=-8`

The solution of the above equation is determined using the quadratic formula which is given as:

`x=(-b\pm √(b^2-4ac))/(2a)`

Plug in
`a=1,b=5,c=-8` and solve for
`x`.

`x=(-5\pm √(5^2-4(1)(-8)))/(2(1))\\x=(-5\pm √(25+32))/(2)\\x=(-5\pm √(57))/(2)\\\\\\\therefore x=(-5-√(57) )/(2)\ or\ x=(-5+√(57) )/(2)`

Therefore, the solutions are:

`x=(-5-√(57) )/(2)\ or\ x=(-5+√(57) )/(2)`