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Which pair shows equivalent expressions?

2x+10=-2(x-5)
0 -2(x+5)=2x-10
-2x-10=-2(x+5)
-2(x–5)=-2X=10​

2 Answers

4 votes

Answer:

C

Explanation:

User Sanjib Debnath
by
6.2k points
2 votes

Answer:

Option 3

Explanation:

We need to find a pair which shows equivalent expressions.

First equation is


2x+10=-2(x-5)


LHS=2x+10


RHS=-2(x-5)=-2(x)-2(-5)=-2x+10


LHS\\eq RHS

Option 1 is incorrect.

Second equation is


-2(x+5)=2x-10


LHS=-2(x+5)=-2(x)-2(5)=-2x-10


RHS=2x-10


LHS\\eq RHS

Option 2 is incorrect.

Third equation is


-2x-10=-2(x+5)


LHS=-2x-10


RHS=-2(x+5)=-2(x)-2(5)=-2x-10


LHS=RHS

Option 3 is correct.

Fourth equation is


-2(x–5)=-2X-10​


LHS=-2(x–5)=-2(x)-2(-5)=-2x+10


RHS=-2x-10


LHS\\eq RHS

Option 4 is incorrect.

Therefore, the correct option is 3.

User Igor Popov
by
5.9k points