For this case we have that by definition, the equation of a line of the point-slope form is given by:
![y-y_ {0} = m (x-x_ {0})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/341t0mqsoqe2qw4gy9ujekvq440bcbjm7u.png)
Where:
m: It's the slope
: It is a point through which the line passes
To find the slope, we need two points through which the line passes, observing the image we have:
![(x_ {1}, y_ {1}): (3, -5)\\(x_ {2}, y_ {2}): (0,4)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {4 - (- 5)} {0-3} = \frac {4 + 5} {-3} = \frac {9} {- 3} = - 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fjhb98j6sd43yckf2nlgnycb9ilcc1way7.png)
Thus, the equation is of the form:
![y-y_ {0} = - 3 (x-x_ {0})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w0em7fl9ids2smwdbqeqd2uny8zdyhsf2x.png)
We choose a point:
![(x_(0), y_ {0}) :( 3, -5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/281w1vkeg1h2evxyxqbxrnr48g7n2xoye0.png)
Finally, the equation is:
![y - (- 5) = - 3 (x-3)\\y + 5 = -3 (x-3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n39mruh9kn04wvfgtbkxvjd99ekeej827m.png)
Answer:
![y + 5 = -3 (x-3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qgpfi5w713clrdvu8hb1tzp52qgdsp3lgx.png)
Option D