Answer:
The given system as (3,3) as its solution.
Explanation:
Here, the given system of the equation is:
4 x + 2 y = 18 ................ (1)
2 x + 3 y = 15 ............... (2)
Now, to use the elimination method, w need to eliminate any of the variable.
Eliminate the variable x in the given system.
Multiply equation (2) with -2 we get,
(2 x + 3 y = 15 )(-2) ⇒ -4x - 6y = -30 ....... (3)
Add (1) and (3), we get:
4 x + 2 y -4x - 6y = 18 -30
or, - 4 y = - 12
or, y = 12/4 = 3 ⇒ y = 3
Putting in (1), we get
4x + 2(3) = 18 or, 4x = 18 - 6 = 12
or, x = 3
(x,y) = (3,3)
Hence, the above system as (3,3) as its solution.