Question

The point-slope form of the equation of the line that passes through (4, -3) and (12, 1) is y-1= 2(x - 12). What is the

standard form of the equation for this line?
OX - 4y=8
O x-4y=2
4x - y = 8
4x - y = 2
co search
д в ее 9

Answer 1

`x - 2y = 10`

Explanation:

We were given the point-slope form equation of the line that passes through (4, -3) and (12, 1) as

`y - 1 = (1)/(2)(x - 12)`

To find the standard form, we expand and rewrite the equation in the form:

`ax + by = c`

where a, b, and c are constants.

`\implies \: y - 1 = (1)/(2) x - 6`

This implies that:

`- 1 + 6 = (1)/(2)x - y`

`\implies \: 5 = (1)/(2)x - y`

Multiply through by 2 to get:

`10 = x - 2y`

We can rewrite to get:

`x - 2y = 10`