Question

A plane designed for vertical takeoff has a mass of 7.5 × 103 kg. Find the net work done on the plane as it accelerates upward at 1.2 m/s2 through a distance of 34.3 m after starting from rest. Answer in units of J.

Answer 1

Net work done,
`W=3.08* 10^5\ J`

Step-by-step explanation:

It is given that,

Mass of the plane,
`m=7.5* 10^3\ kg`

Acceleration of the plane,
`a=1.2\ m/s^2` (upwards)

Distance covered, d = 34.3 m

We need to find the net work done on the plane as it accelerates upward. The product of force and the distance covered is equal to work done. It is given by :

`W=F* d`

`W=m* a* d`

`W=7.5* 10^3\ kg * 1.2\ m/s^2 * 34.3\ m`

W = 308700 J

or

`W=3.08* 10^5\ J`

So, the net work done on the plane is
`3.08* 10^5\ J`. Hence, this is the required solution.