Question

jenny's model train is set up on a circular track. There are six telephone poles evenly spaced around the track. It takes the engine of her train 10 seconds to go from the first pole to the third pole. How long would it take for the engine to go the entire distance around the track?

Answer 1

T = 60 s

Step-by-step explanation:

There are 6 poles on the track which are equally spaced

so the angular separation between the poles is given as

`\theta = (2\pi)/(6)`

`\theta = (\pi)/(3)`

so the angular speed of the train is given as

`\omega = (\theta)/(t)`

`\omega = (\pi)/(30) rad/s`

now we have time period of the train given as

`T = (2\pi)/(\omega)`

`T = (2\pi)/((\pi)/(30))`

`T = 60 s`