Question

A 144.7 g piece of metal has a density of 7.57 g/mL. A 100 mL graduated cylinder contains 25.9 mL of water. What is the final volume after the metal is added to the graduated cylinder?

Answer 1

`V_F=45.0mL`

Step-by-step explanation:

Hello,

In this case, we firstly must compute the volume of the piece of metal by using its density as shown below:

`\rho =(m)/(V)\\V=(m)/(\rho)=(144.7g)/(7.57g/mL)=19.11mL`

Then, by adding the initial volume of water and the volume of the metal, one obtains the final volume:

`V_F=25.9mL + 19.1mL\\V_F=45.0mL`

Best regards.