Answer:
Tom drove the truck for a distance of 89 miles.
Explanation:
Base fee of truck = $18.99
Additional charge per mile = $0.75 per mile
Amount paid by Tom for the rented truck = $160.74
Let us assume Tom drove the truck for a distance of
miles.
So, for
miles they would charge in dollars as:
⇒
![\textrm{ Base fee+ (Additional charge times miles driven) }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/louc5bgj75o682zk6m98oto8neyr51zc15.png)
⇒
![18.99+(0.75* m)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h7t864gnzdlycegehv1kuqjqdsfeb7oyth.png)
⇒
![18.99+0.75\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a5wwfcf9awqr8tqes6bfne1x3dwn8p1x2g.png)
We know the actual amount charge, so we can equate.
![18.99+0.75\ m=160.74](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4v02mve8ib4bzwkb846y7h1fmzyefg8t04.png)
Subtracting both sides by 18.99 to cancel 18.99 on left side.
![18.99+0.75\ m-18.99=160.74-18.99](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kj2a7zjatyjpk1qkkzwm0tuy0hsdk2rodl.png)
![0.75\ m=160.74-18.99](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t0139it6ziof5pux203diycw39k65syyyg.png)
![0.75\ m=141.75](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fyhejr6cdxkj0050sszwbze20crr606a3u.png)
dividing both sides by 0.75 to isolate
![m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cq4we7rbaw8mvm9yuf211b2ffjo45x6v6x.png)
![(0.75\ m)/(0.75)=(141.75)/(0.75)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/euc169lms9d9litganqu70xplmmxor0701.png)
![m=89](https://img.qammunity.org/2020/formulas/mathematics/middle-school/peq2g720ckqad9kgyedoyim9isjdd9xk8g.png)
∴ Tom drove the truck for a distance of 89 miles.