Question

Two friends are pushing a stalled,

1610 kg car. The first pushes with
a 107 N forward force. The car
accelerates at 0.123 m/s . How much
force does the second person exert?
(Unit = N)​

Answer 1

91.03 N

Step-by-step explanation:

consider the way the forces are acting on the car , in the graph

assume the car is accelerating to the right

we can apply Newton's second law of motion (F = ma )

→ F = ma

Fpush + 107 = 1610 * 0.123

Fpush = 91.03 N

second guy is applying 91.03 N force on the car