Answer:
Average velocity is 0.296 m/s.
Average speed is 4.0 m/s.
Step-by-step explanation:
Given:
Distance of the circular track is,

Number of laps ran is,

Time taken for the run is,

Now, total distance covered in 5.4 laps =

Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.
Distance covered in 0.4 laps is,

Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.
Now, average velocity is given as:

Average speed is the ratio of total distance covered to total time taken.
So, average speed =
