Question

Solve using quadratic formula
5x^2-4x+3=0

Answer 1

Impossible

Explanation:

In 5x^2-4x+3=0, standard form, substitute these values in the quadratic formula:

a = 5; b = -4; c = 3

The quadratic formula is
`x = \frac{ -b ± \sqrt{b^(2) - 4ac}}{2a}`

(ignore the weird capital A)

Substitute a b and c:

`x = \frac{-(-4) ± \sqrt{(-4)^(2) - 4(5)(3)}}{2(5)}`

Simplify:

`x = (4) ± √(16 - 60))/(10)`

Because
`√(16-60)` is the square root of a negative number, the answer would be imaginary.

Therefore, there are not solutions to this equation.

A solution is the same as the roots or zeroes, where the graph would cross the x-axis when graphed.

The graph never meets the x-axis. It looks like this: