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An exit poll of 1000 randomly selected voters found that 515 favored measure A. a. Construct a 99% confidence interval for the support of measure A. b. Suppose measure A needs at least 50% support to pass, what are the null and alternative hypotheses if we were to test to see if measure A will pass? c. Compute the p-value of the above test.

User Karan Maru
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1 Answer

3 votes

Answer:

Explanation:

Given that an exit poll of 1000 randomly selected voters found that 515 favored measure A.

Sample proportion p =
(515)/(1000) =0.515


q=1-0.515 =0.485\\n =1000\\SE = \sqrt{(pq)/(n) } \\=0.158\\

Margin of error 99% = 2.58*SE

=
2.58*0.0158\\=0.0408

99% confidence interval =
(0.515-0.0408, 0.515+0.0408)\\= (0.474, 0.556)

------------------------


H_0: p =0.5\\H_a: p >0.5\\

(Right tailed test)

STd error =
\sqrt{(0.5*0.5)/(1000) } \\=0.0158

Test statistic Z = p diff/std error =
(0.015)/(0.0158) \\\\=0.9487

p value = 0.1714

User Paul Kuliniewicz
by
8.2k points
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