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Answer:

Q16.

Quadrant II is (- , +)

I choose the point (-1, 1) and the slope 1.

Substitute point and slope into the formula to find b.

y = mx + b

1 = (1)(-1) + b

b = 2

The equation is y = x + 2

Q15.

The slope is represented by the m value in y=mx+b. Choose a random negative value for m. I will make b 0 so I don't need to write it.

y= -x (slope is negative 1)

Q14.

m = 5; (-6,1)

Sub m and point into y=mx+b; isolate for b.

y=mx+b

1=5(-6)+b

1 = -30 + b

b = 31

Sub b=31 and m=5 into equation of a line

The equation is y = 5x + 31

Q13.

Find slope:

Choose points (0, 8) and (1, 10)

m = (y2-y1)/(x2-x1) = (10-8)/(1-0) = 2/1 = 2

Find b by substituting slope and point (0,8) into equation of a line

y=mx+b

8=2(0)+b

8 = 2 + b

b = 6

Sub b=6 and m=2 into y=mx+b

The equation of the line is y=2x+6

Q12.

Find slope between (5,2) and (6,4)

m = (y2-y1)/(x2-x1) = (4-2)/(6-5) = 2/1 = 2

Find b by substituting slope and point (5,2) into equation of a line

y=mx+b

2 = 2(5) + b

2 = 10 + b

b = -8

Sub b= -8 and m=2 to find equation

The equation of the line is y=2x-8

Q11.

Sub m= -4 and point (5,9) into the equation of a line, isolate b

y=mx+b

9 = -4(5) + b

9 = -20 + b

b = 29

Sub b=29 and m= -4 into the equation of a line

The equation of a line is y = -4x + 29

User Shubhang Malviya
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