Answer:
0.03192 M
Step-by-step explanation:
We are given;
- Initial volume before dilution, V1 = 15.0 mL or 0.015 L
- Volume after dilution, V2 = 125.0 mL or 0.125 L
- Concentration after dilution, M2 = 0.00383 M
We are required to calculate the initial concentration, M1 before dilution.
- To answer the question, we will use the dilution formula;
- Dilution formula is given by; M1V1 = M2V2
Rearranging the formula;
M1 = M2V2 ÷ V1
= ( 0.00383 M × 0.125 L) ÷ 0.015 L
= 0.03192 M
Therefore, the original concentration of the solution before dilution is 0.03192 M