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A running track in the shape of an oval is shown. The ends of the track form semicircles.

What is the perimeter of the inside of the track?

(π = 3.14)

392.00 m
372.22 m
444.44 m
588.88 m

A running track in the shape of an oval is shown. The ends of the track form semicircles-example-1
User Phdstudent
by
6.7k points

2 Answers

12 votes

Answer:

Two semi circles would equal one circle.

The perimeter of a circle is PI x diameter.

The diameter of the circle is shown as 56 m

The perimeter of the 2 ends = 56 x 3.14 = 175.84

The length of the inside of the track is given as 130 m, and there are 2 sides so 130 + 130 = 260 m.

Total perimeter = 260 + 175.84 = 435.84 m.

Explanation:

User Dpeacock
by
6.7k points
3 votes

Answer:

The first one answer is for a different equation. I have this test and got to FLVS. This is the right answer.

Explanation:

SInce the length is 150 on one side you multiply it twice. 150*2=300

Then you find the circumference which is 46.

Then, you solve 80+46(3.14)

You multiply 46*3.14= 144.44.

Then you add 144.44 to 300 which gets you 444.44

User ItzDavi
by
6.5k points
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