Question

You place a 0.17 kg can of soup and a 0.31 kg jar of pickles on the kitchen counter, separated by a distance of 0.42 m. What is the magnitude of the force of gravity that the can of soup exerts on the jar of pickles?

Answer 1

`1.984 * 10^(-11) \mathrm{N} \text { is the force of gravity exerted on the jar of pickles. }`

Step-by-step explanation:

According to Newton's third law that each force has an equal and opposite reaction force in this case both of the jars will exert the same force an each other

. The force is given by

`\mathrm{F}=(G * M_(1) * M_(2))/(r^(2))`

Where, F = force,
`G=\text { gravitational constant }=\left(6.67 * 10^(-11)\right)`,
`mass \left(\mathrm{M}_(1)\right)=0.17 \mathrm{kg}`,
`mass \left M_(2)= 0.31 \mathrm{kg}` and Distance(r) = 0.42 m.

Substitute the values in the formula.

`\mathrm{F}=(6.67 * 10^(-11) * 0.17 * 0.31)/(0.42^(2))`

`\mathrm{F}=(3.51 * 10^(-12))/(0.176)`

`\mathrm{F}=1.984 * 10^(-11) \mathrm{N}`

`\text { The force of gravity exerted on the jar of pickles is } 1.984 * 10^(-11) \mathrm{N} \text { . }`