Answer:
The other end point of the segment with mid point (5,2) is (13, -1).
Explanation:
Here, let the endpoints of the segment are A (-3,5) and B (x,y)
The mid point of the segment AB is C(5,2).
Now, by MID POINT FORMULA:
If the Points P(a,b) and Q(c,d) have S(x,y) as their mid points, then
![(x,y) =( (a+c)/(2) , (b+d)/(2) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gfxfgf066evp3w279zai4ui0e4vvq6li18.png)
Similarly, here:
![(5,2) =( (-3+x)/(2) , (5+y)/(2) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u7t27zqwr4ul60p3v2gwztqgoy8rbmz3v0.png)
⇒
![5 = (-3+x)/(2), 2 = (5+y)/(2) \\\impliesc10 = -3 +x , 4 = 5 + y\\\implies x = 10 + 3, y = 4-5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kz7oypkhb69pslvg82nuq5k6wkuf7dkrfb.png)
or, x = 13 and y = -1
⇒B(x,y) = (13,-1)
Hence the other end point of the segment with mid point (5,2)
is (x,y) = (13, -1)