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Helicopter blades withstand tremendous stresses. In addition to supporting the weight of a helicopter, they are spun at rapid rates and experience large centripetal accelerations, especially at the tip. Calculate the centripetal acceleration at the tip of a 3.50 m long helicopter blade that rotates at 370 rev/min.

User Bratan
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1 Answer

2 votes

Answer:
5255.46 m/s^2

Step-by-step explanation:

Given

length of blade
L=3.5 m


N=370 rev/min

Angular velocity
\omega =(2\pi N)/(60)


\omega =38.75 rad/s

Centripetal acceleration is given


a_c=\omega ^2\cdot L


a_c=38.75^2\cdot 3.5


a_c=5255.468 m/s^2

User Sinanspd
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