Question

A sealed balloon is filled with 1.00 L of helium at 19°C and 1.09 atm. The balloon rises to a point in the atmosphere where the pressure is 222 torr and the temperature is −28 °C. What is the change in the volume of the balloon as it ascends from 1.09 atm to a pressure of 222 torr?

Answer 1

change in volume of ballon is 2.109 L

Step-by-step explanation:

Given data:

initial temperature = 199 degree C = 292 K

pressure P1 = 1.09 atm

initial volume = 1.00 L

pressure P2 = 222 torr = 0.292 atm

temperature T2 = - 28 oC = 245 K

we know that
`(P1 V1)/(T1) = (P2 V2)/(T2)`

`(1.09 *  1)/(292) = (0.292 *  V2)/(245)`

V2 = 3.109 L

change in volume of ballon = 3.109 - 1 = 2.109 L