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Suppose that f(1) = 1, f(4) = 5, f '(1) = 3, f '(4) = 3, and f '' is continuous. find the value of 4 1 xf ''(x) dx.

User Jeyan
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2 Answers

24 votes
24 votes

Final answer:

The value of the integral of f''(x) from 1 to 4 is 0, since the derivative f'(x) is the same at both endpoints, indicating no net change.

Step-by-step explanation:

The question asks us to find the value of the integral of f''(x) from 1 to 4, which can be approached using the Fundamental Theorem of Calculus. Since f'(x) represents the derivative of f(x), the integral of f''(x) from 1 to 4 will give us the change in f'(x) over that interval, which is f'(4) - f'(1). Given that f'(1) = 3 and f'(4) = 3, the change is 3 - 3 = 0. Hence, the integral ∫_1^4 f''(x) dx = 0.

User Marsh Ray
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2.8k points
12 votes
12 votes

Answer: b

Step-by-step explanation:

I think

User Bug Hunter Zoro
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