Answer:
A. Total Money Contributed after n months =
![\$ 3000 + \$ (500* n)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x9oi12kxi40ablpjldqlznez0hsj8iauoh.png)
B. Total Money Contributed after 24 months =
![\$ \ 15000](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5x54hv9wvic01tho97ardsxocfu0j3hpg.png)
Explanation:
Given:
Initial contribution =
![\$\ 3000](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x5lnzm32oyob5kd5gpgw4wiljrixdtzr4b.png)
each month contribution =
![\$\ 500](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mmotmm6a19b7gnq5htdqy5lpbnjit5sc59.png)
After 1 month contributed =
![\$\ 3000 + \$\ 500 * 1= \$ \ 3500](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1gly6y7p1d46g1511vu7ixpg75vkx39y07.png)
Solving for Part A
let n be the number of months
∴ Total Contribution after n months = Initial contribution + (each month contribution
Number of months =
![\$\ 3000 + \$\ 500 * n](https://img.qammunity.org/2020/formulas/mathematics/middle-school/igvsddpo9i661h0lo1t113k6geyvghqt5c.png)
Solving for Part A
Now n= 24 months
∴ Total Contribution after 24 months =
![\$\ 3000 + \$\ 500 * 24 = \$\ 3000 + \$\ 12000= \$\ 15000](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cynvytdfr47tqen7syz4jrv4m7xfmksnkt.png)