Answer:
The average cost of each tape is
![(45)/(v)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/piv6dfwz5nafp9x9r1snrbbc8bto91wuwr.png)
Explanation:
Total number of tapes bought = v tapes
Total cost paid for v tapes = $45
By UNITARY METHOD:
If the cost of n objects is A.
Then the unit price is
![\frac{\textrm{Total cost of n objects}}{\textrm{Number of the objects}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g0glud2u7q3ryt11c4dnyfvkpnviiwdgh5.png)
Cost of v tapes = $45
⇒ Cost of 1 tape =
![\frac{\textrm{Total cost of v tapes}}{\textrm{v}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zt4q4gfmc2lj5unu4xubur63rawz66ggel.png)
=
![(45)/(v)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/piv6dfwz5nafp9x9r1snrbbc8bto91wuwr.png)
Hence, the average cost of each tape is
![(45)/(v)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/piv6dfwz5nafp9x9r1snrbbc8bto91wuwr.png)