Question

If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular coil of wire with diameter 40 cm and 500 coils? The coil rotates through a magnet field of magnitude 9e-3 T which is directed such that the angle between the area vector and the magnet field vector varies from 0 to 2 π radians.

Answer 1

Angular velocity,
`\omega=35.36\ rad/s`

Step-by-step explanation:

It is given that,

Maximum emf generated in the coil,
`\epsilon=20\ V`

Diameter of the coil, d = 40 cm

Radius of the coil, r = 20 cm = 0.2 m

Number of turns in the coil, N = 500

Magnetic field in the coil,
`B=9* 10^(-3)\ T`

The angle between the area vector and the magnet field vector varies from 0 to 2 π radians. The formula for the maximum emf generated in the coil is given by :

`\epsilon=NBA\omega`

`\omega=(\epsilon)/(NBA)`

`\omega=(20\ V)/(500* 9* 10^(-3)\ T* \pi (0.2\ m)^2)`

`\omega=35.36\ rad/s`

So, the angular velocity of the circular coil is 35.36 rad/s. Hence, this is the required solution.