Question

A line has a slope of 3 and passes through the points (12,5). What is the equation of this line?

Answer 1

`y=3x-31`

Explanation:

The equation of a line is given as:

`y=mx+b`

Where

m is the slope

b is the y intercept (y-axis cutting point)

First, we see that the slope is given as 3, so,

m = 3

Also, the point is given as (12,5) [(x,y)], so we can say:

x = 12

y = 5

Now, we can write (with slope = 3):

y = 3x + b

Now plugging in x, and y values:

5 = 3(12) + b

5 = 36 + b

b = -31

Thus, equation of line is:

`y=mx+b\\y=3x-31`