Question

At exactly 2:00 PM, speedy the hermit crab crawl onto a meter stick starting at the 10 cm mark. If he reaches the 60 cm mark at exactly 2:10 PM, what is his speed?

Answer 1

speed=5cm/minute

Step-by-step explanation:

Given at 2:00PM the hermit is at 10cm mark

Also given that the hermit reaches 60cm mark at 2:10PM

Therefore the time elapsed is 10 minutes =
`10* 60=600 seconds`

the distance travelled by the hermit is 60-10=50cm=0.5m

We know that

`speed=(distane)/(time)`

`speed=(0.5)/(600)`

speed =
`8.3* 10^(-4)` m/sec=5cm/minute