Solving the quadratic equation , x=0.607,4.107
Explanation:
Given the quadratic equation:
![2x^2+7x-5=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/njnsg0qnijy7la0cq6bd2ns2amfnpsl5gc.png)
Quadratic formula:
One way of solving a quadratic equation on the form of
is to used the quadratic formula. It tells us that the solutions of the quadratic equation are
[/tex]
where
a≠0 and
b2−4ac≥0
So, we can see that the above equation is a quadratic equation and we will solve this equation by using the discriminant method.
So, according to question, we have
a = 2
b = 7
c = -5
Substituting the values in Quadratic formula, we have
![x=\frac{(-7) \pm\left\sqrt{(7^(2)-(4 * 2 *-5)\right)}}{2 * 2}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lfxu5rr6lxqe21v2ok8a6dhowcmzyioisl.png)
![x=((-7) \pm\left√((49-(-40)\right)))/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ru8rg1gceo1k81j24m4tfyw4fsj7p86k0f.png)
![x=((-7) \pm\left√((49+40)\right)))/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hj3k2ykkqpmnmxicyrij79pqww8b2r23b4.png)
![x=((-7) \pm9.433)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4r60itmve2kpobn39ml75nvxbxt9jdnuqi.png)
![x=((-7)-9.433)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fdlf1r9qnvmauf67skmzb19epajbuln6kb.png)
=
![x=((-7)-9.433)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fdlf1r9qnvmauf67skmzb19epajbuln6kb.png)
![x=(16.433)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gvk53xzyc6qmkrvhjlfd0vrv2anddearov.png)
x=0 0.608 x= 4.107
So, we will get the values of x=0.607,4.107